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1022_Physics ProblemsTechnical Physics

1022_Physics ProblemsTechnical Physics - Chapter 36*P36.38...

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Chapter 36 363 *P36.38 In 1 1 1 p q f + = p q + = 1 1 constant, we differentiate with respect to time = 1 1 0 2 2 p dp dt q dq dt e j e j dq dt q p dp dt = 2 2 . We must find the momentary image location q : 1 20 1 1 0 3 m m + = q . q = 0 305 . m. Now dq dt = − = − = 0 305 20 5 0 001 16 1 16 2 2 . . . m m m s m s mm s toward the lens a f a f . *P36.39 (a) 1 1 1 p q f + = 1 480 1 1 7 00 cm cm + = q . q = 7 10 . cm (b) M h h q p = = − ′ = = = − h hq p 5 00 7 10 480 0 074 0 . . . mm cm cm mm a fa f diameter of illuminated spot = 74 0 . m µ (c) I A d = = = × = × P P 4
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