1022_Physics ProblemsTechnical Physics

1022_Physics ProblemsTechnical Physics - Chapter 36 *P36.38...

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Chapter 36 363 *P36.38 In 111 pq f += pq −− 11 constant, we differentiate with respect to time −−= 110 22 p dp dt q dq dt ej dq dt q p dp dt = 2 2 . We must find the momentary image location q : 1 20 03 m m q . q = 0305 . m . Now dq dt =− = 20 5 0 00116 116 2 2 . .. m m ms mms toward the lens af a f . *P36.39 (a) 1 480 700 cm cm q . q = 710 c m (b) M h h q p = ′= = h hq p 500 480 00740 . mm cm cm mm a f diameter of illuminated spot = 74 0 . m µ (c) I A d == = × PP 4 0100 74 0 10 233 10 2 6 2 7 π . . . W4 m Wm 2 P36.40
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