1029_Physics ProblemsTechnical Physics

# 1029_Physics ProblemsTechnical Physics - 370 P36.59 Image...

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370 Image Formation P36.59 (a) 1 1 11 12 f n RR =− F H G I K J af 1 65 0 166 1 1 50 0 1 2 F H G I K J . . . cm cm R 50 0 1 42 9 2 R =+ .. cm cm so R 2 23 1 = . cm (b) The distance along the axis from B to A is D B R 1 R 2 2.00 cm A C FIG. P36.59 2 22 2 2 00 50 0 50 0 2 00 0 040 0 −− = = . . . cm cm cm cm cm . Similarly, the axial distance from C to D is 23 1 23 1 2 00 0 086 8 cm cm cm cm = . Then, AD + = 0 100 0 040 0 0 086 8 0 147 . . cm cm cm cm . *P36.60 We consider light entering the rod. The surface of entry is convex to the object rays, so R 1 450 c m n p n q nn Rq q q 1 1 2 1 21 1 1 133 100 150 150 133 150 00378 00133 00245 613 += =−= = . . . . ... . cm cm cm cm cm cm The first image is real, inverted and diminished. To find its magnification we can use two similar triangles in the ray diagram with their vertices meeting at the center of curvature: V C O 1 I 1 V C O 2 I 2 FIG. P36.60 h h h h 1 1 1 1 100 4 5 61 3 4 5 0543 cm cm cm cm + = . . . Now the first image is a real object for the second surface at object distance from its vertex
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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