372 Image FormationP36.62111110 0112 5qfp=−=−..cmcmsoq150 0=. cm (to left of mirror).This serves as an object for the lens (a virtual object), so116 7125 0222p−−−cmcmafand q250 3=−. cm,meaning 50.3 cm to the right of the lens. Thus, the final image is located25 3. cm to right of mirror .MqpMqpMMM1112221250 040050 325 0201805−−==......cm12.5 cmcmcmafafThus, the final image is virtual, upright, 8.05 times the size of object, and 25.3 cm to right of themirror.P36.63We first find the focal length of the mirror.110 01800940 0fpq=+=+=.cmcmcmandf=444cm.Hence, if p=20 0cm,1120 015 5688 8qfp−=..cmcmcm.Thus,q=571cm , real.*P36.64A telescope with an eyepiece decreases the diameter of abeam of parallel rays. When light is sent through the samedevice in the opposite direction, the beam expands. Send
This is the end of the preview.
access the rest of the document.