372 Image FormationP36.62111110 0112 5qfp=−=−..cmcmsoq150 0=. cm (to left of mirror).This serves as an object for the lens (a virtual object), so116 7125 0222p−−−cmcmafand q250 3=−. cm,meaning 50.3 cm to the right of the lens. Thus, the final image is located25 3. cm to right of mirror .MqpMqpMMM1112221250 040050 325 0201805−−==......cm12.5 cmcmcmafafThus, the final image is virtual, upright, 8.05 times the size of object, and 25.3 cm to right of themirror.P36.63We first find the focal length of the mirror.110 01800940 0fpq=+=+=.cmcmcmandf=444cm.Hence, if p=20 0cm,1120 015 5688 8qfp−=..cmcmcm.Thus,q=571cm , real.*P36.64A telescope with an eyepiece decreases the diameter of abeam of parallel rays. When light is sent through the samedevice in the opposite direction, the beam expands. Send
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