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1033_Physics ProblemsTechnical Physics

# 1033_Physics ProblemsTechnical Physics - 374 Image...

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374 Image Formation P36.67 From the thin lens equation, q f p p f 1 1 1 1 1 6 00 12 0 12 0 6 00 4 00 = = − − = − . . . . . cm cm cm cm cm a fa f a f . When we require that q 2 → ∞ , the thin lens equation becomes p f 2 2 = . In this case, p d 2 4 00 = − − . cm a f . Therefore, d f + = = 4 00 12 0 2 . . cm cm and d = 8 00 . cm . FIG. P36.67 *P36.68 The inverted real image is formed by the lens operating on light directly from the object, on light that has not reflected from the mirror. For this we have M q p = − = − 1 50 . q p = 1 50 . 1 1 1 p q f + = 1 1 1 50 1 10 2 50 1 50 p p p + = = . . . cm p = F H G I K J = 10 2 5 1 5 16 7 cm cm . . . Then the object is distant from the mirror by 40 0 16 7 23 3 . . . cm cm cm = . The second image seen by the person is formed by light that first reflects from the mirror and then goes through the lens. For it to be in the same position as the inverted image, the lens must be receiving light from an image formed by the mirror at the same location as the physical object. The
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