1035_Physics ProblemsTechnical Physics

1035_Physics ProblemsTechnical Physics - 376 P36.72 Image...

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376 Image Formation P36.72 (a) The lens makers’ equation, 1 1 11 12 f n RR =− + F H G I K J af becomes: 1 500 1 1 900 1 11 0 .. . cm cm cm L N M O Q P n giving n = 199 . . (b) As the light passes through the lens for the first time, the thin lens equation 111 pq f += becomes: 1 800 1 cm cm q or q 1 13 3 = . cm, and M q p 1 1 1 13 3 167 . . cm 8.00 cm . This image becomes the object for the concave mirror with: m =−= 20 0 20 0 13 3 6 67 1 . . cm cm cm cm and f R == + 2 400 . c m . The mirror equation becomes: 1 667 cm cm q m giving q m = 10 0 cm and M q p m m 2 10 0 150 . . cm 6.67 cm . The image formed by the mirror serves as a real object for the lens on the second pass of the light through the lens with: m 3 20 0 10 0 = + cm cm. The thin lens equation yields: 1 10 0 3 cm cm q or q 3 10 0 = and M q p 3 3 3 10 0 100 . . cm 10.0 cm . The final image is a real image located 10 0 . cm to the left of the lens
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