{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

1047_Physics ProblemsTechnical Physics

1047_Physics ProblemsTechnical Physics - 388 P37.19...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
388 Interference of Light Waves P37.19 (a) From Equation 37.8, φ π λ θ π λ φ π λ π = = + = × × × = 2 2 2 2 0 850 10 2 50 10 600 10 2 80 7 95 2 2 3 3 9 d d y y D yd D sin . . . . m m m m rad e je j e j a f (b) I I d d m max max cos sin cos sin cos cos = = 2 2 2 2 2 π λ θ π λ θ φ π b g b g b g I I max cos cos . . = = F H G I K J = 2 2 2 7 95 0 453 φ rad 2 P37.20 (a) The resultant amplitude is E E t E t E t r = + + + + 0 0 0 2 sin sin ω ω φ ω φ b g b g , where φ π λ θ = 2 d sin . E E t t t t t E E t E t E E t t E t r r r = + + + + = + + + + = + + = + + 0 0 2 0 0 0 2 2 1 2 1 2 1 2 1 2 sin sin cos cos sin sin cos cos sin sin cos cos cos sin sin cos cos sin cos cos sin cos sin ω ω φ ω φ ω φ ω φ ω φ φ ω φ φ φ φ ω φ ω φ φ ω φ b g b g e j b gb g b gb g b g b g Then the intensity is I E E r = + F H G I K J 2 0 2 2 1 2 1 2 cos φ b g where the time average of sin 2 ω φ t + b g is 1 2 . From one slit alone we would get intensity I E max F H G I K J 0 2 1 2 so I I d = + F H G I K J L N M O Q P max cos
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern