1047_Physics ProblemsTechnical Physics

1047_Physics ProblemsTechnical Physics - 388 P37.19...

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388 Interference of Light Waves P37.19 (a) From Equation 37.8, φ π λ θ == + ≈= ×× × = −− 22 2 2 0 850 10 2 50 10 600 10 2 80 795 33 9 dd y yD yd D sin .. . . m m m rad ej e j a f (b) I I d d m max max cos sin cos sin cos cos 2 2 2 2 2 πλ θ bg I I max cos cos . . F H G I K J = 2 0453 rad 2 P37.20 (a) The resultant amplitude is EE tE t E t r =+ + + + 00 0 2 sin sin ωω ω b g , where = 2 d sin . t t t t t t E t t t E t r r r = +++ + + + + + + 0 0 2 0 12 1 2 sin sin cos cos sin sin cos cos sin sin cos cos cos sin sin cos cos sin cos cos sin cos sin ωφ φωφ φω b g b g b g Then the intensity is IE E r ∝= + F H G I K J 2 0 2 2 1 2 cos where the time average of sin 2 t + is 1 2 . From one slit alone we would get intensity IE max F H G I K J 0 2 1 2 so II d F H G I K J L N M O Q P max cos sin 2 2 πθ . (b) Look at the N = 3 graph in Figure 37.14. Minimum intensity is zero, attained where
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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