1050_Physics ProblemsTechnical Physics

# 1050_Physics ProblemsTechnical Physics - Chapter 37 P37.27...

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Chapter 37 391 P37.27 See the figure to the right: φ π = 2 . ω t π /2 π /2 π /2 FIG. P37.27 P37.28 E E E E E R 2 1 2 2 2 1 2 2 = + cos β where β φ = 180 . Since I E 2 I I I I I R = + + 1 2 1 2 2 cos φ . β E 1 = π /4 φ E 2 E R FIG. P37.28 P37.29 Take φ = ° 360 N where N defines the number of coherent sources. Then, E E t m R m N = + = = 0 1 0 sin ω φ b g . In essence, the set of N electric field components complete a full circle and return to zero. x y The N = 6 case φ = 360 ° N = 360 ° 6 = 60. 0 ° 60.0° FIG. P37.29 Section 37.5 Change of Phase Due to Reflection Section 37.6 Interference in Thin Films
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