398 Interference of Light WavesTo go through 200 bright fringes, the change in thickness of the air film must be:2002100λFHGIKJ=.Thus, the increase in the length of the rod is∆L==×=×−−100100 5 00 105 00 1075..m mej.From∆∆LL ti=αwe have:×°=×°−∆∆LLTi500 10010025020 0 10561..mmCCafaf.P37.50Since 1125134<<, light reflected from top and bottom surfaces of the oil undergoes phase reversal.The path difference is then 2t, which must be equal tommnn=for maximum reflection, with m=1 for the given first-order condition and n=125.. Sotmn=215002125200nmnmaf..The volume we assume to be constant:100200. mnm3=AA×=−200 1050096.mmkm322.P37.51One radio wave reaches the receiver Rdirectly from the distantsource at an angle θabove the horizontal. The other waveundergoes phase reversal as it reflects from the water at
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .