1064_Physics ProblemsTechnical Physics

# 1064_Physics ProblemsTechnical Physics - 405 Chapter 37...

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Chapter 37 405 *P37.68 Depth = one-quarter of the wavelength in plastic. t n == = λ 4 780 130 nm 41 .50 nm a f P37.69 2 1 2 hm sin θλ =+ F H G I K J bright 2 2 1 2 h y L F H G I K J = so h L y × × = 2 200 606 10 212 10 0505 9 3 . . . m m m mm af ej *P37.70 Represent the light radiated from each slit to point P as a phasor. The two have equal amplitudes E . Since intensity is proportional to amplitude squared, they add to amplitude 3 E . Then cos θ = 32 E E , 30 . Next, the obtuse angle between the two phasors is 180 30 30 120 −−= ° , and φ =− ° = ° 180 120 60 . The phase difference between the two phasors is caused by the path difference δ SS SS 21 according to = ° 360 , δλ = ° ° = 60 360 6 . Then Ld L L 22 222 2 6 2 63 6 +− = +=+ + λλ The last term is negligible d L = F H G I K J = × = 2 6 212 620 10 0498 12 9 . . m 6 mm . E E 3 E FIG. P37.70
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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