1077_Physics ProblemsTechnical Physics

# 1077_Physics ProblemsTechnical Physics - 418 * P38.30...

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418 Diffraction Patterns and Polarization * P38.30 For a side maximum, tan . θ µ == y L 04 m 6.9 m 332 . dm sin θλ = d = × ° = 17 8 0 1 0 13 5 9 af ej m m sin . . . The number of grooves per millimeter = × × = 11 0 74 2 3 m 13.5 10 m -6 . . FIG. P38.30 P38.31 (a) Nm = λ N 1 531 7 2800 a f . nm 0.19 nm (b) 132 10 472 2 . . × = m m P38.32 d × = 1 4200 238 10 2380 6 cm m n m . . sin = or = F H G I K J sin 1 m d and yL L m d F H G I K J L N M O Q P tan tan sin 1 . Thus, m d m d = F H G I K J L N M O Q P F H G I K J L N M O Q P R S T U V W −− tan sin tan sin 1 2 1 1 λλ . For m = 1 , y = F H G I K J L N M M O Q P P F H G I K J L N M M O Q P P R S | T | U V | W | = 200 589 6 589 0554 .t a n s i n . tan sin . m m a f . For m = 2 , y = F H G I K J L N M M O Q P P F H G I K J L N M M O Q P P R S | T | U V | W | = 25896 2589 154 a n s i n . tan sin . m m a f a f a f . For
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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