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1080_Physics ProblemsTechnical Physics

# 1080_Physics ProblemsTechnical Physics - Chapter 38...

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Chapter 38 421 P38.42 (a) θ 1 20 0 ., 2 40 0 3 60 0 . II I fi f =− ° = °°° = cos cos cos . cos . cos . cos . . 2 1 2 21 2 32 222 0 10 0 20 0 20 0 20 0 689 θθ bg b g b g a fafafaf units units (b) 1 0 , 2 30 0 3 60 0 . FIG. P38.42 I f = = 10 0 0 30 0 30 0 5 63 22 2 . cos cos . cos . . units units a fa fafaf P38.43 By Brewster’s law, n p == ° = tan tan . . 48 0 1 11 af . *P38.44 (a) At incidence, nn 11 sin sin = and ′= . For complete polarization of the reflected light, 90 90 90 90 12 +−= ° +==+ Then n 2 12 1 90 sin sin cos = sin cos tan 1 1 2 1 1 n n At the bottom surface, = because the normals to the surfaces of entry and exit are parallel. Then 23 14 sin sin = and 33 sin sin = and 41 = n 1 n 2 1 1 ' n 1 3 3 ' 2 4 FIG. P38.44(a) The condition for complete polarization of the reflected light is 90 90 90 34 −′+ − = ° 90 += This is the same as the condition for 1 to be Brewster’s angle at the top surface. (b) We consider light moving in a plane perpendicular to the line where the surfaces of the prism meet at the unknown angle Φ . We require 90 sin sin = +=° So 2 2 90 sin sin −= n n 1 2 2 = tan
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