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1085_Physics ProblemsTechnical Physics

1085_Physics ProblemsTechnical Physics - 426 P38.60...

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426 Diffraction Patterns and Polarization P38.60 (a) We require θ λ min . = = = 1 22 2 D L D L radius of diffraction disk . Then D L 2 2 44 = . λ . (b) D = × = 2 44 500 10 0 150 428 9 . . m m m e j a f µ P38.61 The limiting resolution between lines θ λ min . . . . = = × × = × 1 22 1 22 550 10 5 00 10 1 34 10 9 3 4 D m m rad e j e j . Assuming a picture screen with vertical dimension A , the minimum viewing distance for no visible lines is found from θ min = A 485 L . The desired ratio is then L A = = × = 1 485 1 485 1 34 10 15 4 4 θ min . . rad e j . P38.62 (a) Applying Snell’s law gives n n 2 1 sin sin φ θ = . From the sketch, we also see that: θ φ β π + + = , or φ π θ β = + b g . Using the given identity: sin sin cos cos sin φ π θ β π θ β = + + b g b g , which reduces to: sin sin φ θ β = + b g . FIG. P38.62(a) Applying the identity again: sin sin cos cos sin φ θ β θ β = + . Snell’s law then becomes: n n 2 1 sin cos cos sin sin
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