1086_Physics ProblemsTechnical Physics

# 1086_Physics - Chapter 38(b 427 L sinb 2g OP where = 2 a sin =M I NM 2 QP 2 b0.060 0 mg sin 15.0 = = 2.44 rad 2 I From Equation 38.4 max When =

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Chapter 38 427 (b) From Equation 38.4, I I max sin = L N M M O Q P P β 2 2 2 bg where πθ λ = 2 a sin . When θ 15 0 ., π = ° = 2 0 060 0 15 0 00400 244 .s i n . . . m m rad and I I max sin . . . = L N M O Q P = 122 0593 2 rad rad af . (c) sin = a so 41 8 .: This is the minimum angle subtended by the two sources at the slit. Let α be the half angle between the sources, each a distance A = 0100 . m from the center line and a distance L from the slit plane. Then, L == ° F H G I K J = A cot . cot . . 41 8 2 0262 m m a f . FIG. P38.63(c) P38.64 I I max cos . cos . ° = 1 2 45 0 45 0 1 8 22 ej P38.65 dm sin θλ = and, differentiating, dd m d cos θθ = or 1 2 −≈ sin ∆∆ d m d m 1 2 so 22 2 . *P38.66 (a) The angles of bright beams diffracted from the grating are given by sin = . The angular dispersion is defined as the derivative d d : d d d m a f
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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