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1088_Physics ProblemsTechnical Physics

# 1088_Physics ProblemsTechnical Physics - Chapter 38...

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Chapter 38 429 P38.69 (a) The E and O rays, in phase at the surface of the plate, will have a phase difference θ π λ δ = F H G I K J 2 after traveling distance d through the plate. Here δ is the difference in the optical path lengths of these rays. The optical path length between two points is the product of the actual path length d and the index of refraction. Therefore, δ = dn dn O E . The absolute value is used since n n O E may be more or less than unity. Therefore, θ π λ π λ = F H G I K J = F H G I K J 2 2 dn dn d n n O E O E . (b) d n n O E = = × = × = λθ π π π µ 2 550 10 2 2 1 544 1 553 1 53 10 15 3 9 5 m m m e j b g . . . . P38.70 (a) From Equation 38.4, I I max sin = L N M M O Q P P β β 2 2 2 b g . If we define φ β 2 this becomes I I max sin = L N M O Q P φ φ 2 . Therefore, when I I max = 1 2 we must have sin φ φ = 1 2 , or
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