1088_Physics ProblemsTechnical Physics

1088_Physics ProblemsTechnical Physics - Chapter 38 P38.69...

This preview shows page 1. Sign up to view the full content.

Chapter 38 429 P38.69 (a) The E and O rays, in phase at the surface of the plate, will have a phase difference θ π λ δ = F H G I K J 2 after traveling distance d through the plate. Here is the difference in the optical path lengths of these rays. The optical path length between two points is the product of the actual path length d and the index of refraction. Therefore, =− dn dn OE . The absolute value is used since n n O E may be more or less than unity. Therefore, = F H G I K J −= F H G I K J 22 dn dn d n n O E . (b) d nn = = × = λθ µ 2 550 10 2 2 1 544 1 553 153 10 153 9 5 m m m ej bg .. P38.70 (a) From Equation 38.4, I I max sin = L N M M O Q P P β 2 2 2 . If we define φ 2 this becomes I I max sin = L N M O Q P 2 . Therefore, when I I max = 1 2 we must have sin = 1 2 , or sin = 2 . (b) Let y 1 = sin and
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online