1098_Physics ProblemsTechnical Physics

1098_Physics ProblemsTechnical Physics - Chapter 39 P39.12...

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Chapter 39 439 P39.12 (a) The spaceship is measured by Earth observers to be of length L , where LL v c p =− 1 2 2 and Lv t =∆ vt L v c p ∆= 1 2 2 and v c p 22 2 2 2 1 F H G I K J . Solving for v , vt L c L p p 22 2 2 2 ∆+ F H G I K J = v cL ct L p p = + . (b) The tanks move nonrelativistically, so we have v == 300 400 m 75 s ms .. (c) For the data in problem 11, v cc c = ×× + = + = 300 3 10 0 75 10 300 300 225 300 0800 8 2 6 2 2 m s m m m af ej e j . . in agreement with problem 11. For the data in part (b), v c = ×+ = = 300 31 0 7 5 3 0 0 300 225 10 300 133 10 8 2 10 2 2 8 m s m m m a f a f . in agreement with part (b). P39.13 We find Cooper’s speed: GMm r mv r 2 2 = . Solving, v GM Rh = + L N M O Q P = × L N M M O Q P P = a f e j 12 11 24 66 6 67 10 5 98 10 637 10 0160 10 782 . k m s . Then the time period of one orbit, T v = + = × × 2 2 6 53 10 782 10 525 10 6 3 3 π . . s . (a) The time difference for 22 orbits is ∆∆
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