1102_Physics ProblemsTechnical Physics

1102_Physics ProblemsTechnical Physics - 443 Chapter 39...

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Chapter 39 443 P39.23 γ = = = 1 1 1 10 9 9 5 10 0 22 2 vc . . We are also given: L 1 200 = . m, and θ 30 0 . (both measured in a reference frame moving relative to the rod). Thus, LL x 11 1 2 00 0 867 1 73 == = cos . . . m m af a f and y 11 1 2 00 0 500 1 00 = sin . . . m a f L x 2 is a proper length, related to L x 1 by L L x x 1 2 = . Therefore, xx 21 10 0 17 3 .. m and yy 100 . m . (Lengths perpendicular to the motion are unchanged). FIG. P39.23 (a) L xy 2 2 2 =+ bg ej gives L 2 17 4 = . m (b) 2 1 2 2 = tan L L y x gives 2 330 . *P39.24 Einstein’s reasoning about lightning striking the ends of a train shows that the moving observer sees the event toward which she is moving, event B , as occurring first. The S -frame coordinates of the events we may take as ( x = 0, y = z = t = 0) and ( x = 100 m, y = z = t = 0). Then the coordinates in S are given by the Lorentz transformation. Event A is at ( ′= x y z t 0). The time of event B is F H G I K J = F H G I K J =− × F H G I K J × tt v c x c c 2 2 2 7 1 8 0 08 100 1 667 80 444 10 . . m m 31 0 m s s 8 . The time elapsing before A occurs is 444 ns . P39.25 (a) From the Lorentz transformation, the separations between the blue-light and red-light
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