1103_Physics ProblemsTechnical Physics

1103_Physics ProblemsTechnical Physics - 444 Relativity...

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444 Relativity Section 39.6 The Lorentz Velocity Transformation Equations P39.26 u x = Enterprise velocity v = Klingon velocity From Equation 39.16 ′= = = u uv uvc cc c x x x 1 0900 0800 1 0 900 0 800 0357 2 .. . af . FIG. P39.26 P39.27 ′ = = −− =− u c x x x 1 0 750 0 750 1 0 750 0 750 0960 2 . a f FIG. P39.27 *P39.28 Let frame S be the Earth frame of reference. Then vc 07 . . The components of the velocity of the first spacecraft are uc c x = 06 50 0386 .c o s . and c y = 0459 .s i n . . As measured from the S frame of the second spacecraft, ′ = = == ′ = = u c c c u u c c c x x x y y x 1 10 3 8 6 0 7 1086 127 0855 1 0459 1 07 3 8 60 7 0 459 0 714 0258 2 2 2 2 . . . . . a fa f ej a fa f a f γ The magnitude of u is 0 855 0 285 0 893 22 . c += and its direction is at tan . . . 1 16 8 c c x above the -axis . Section 39.7 Relativistic Linear Momentum and the Relativistic Form of Newton
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