Chapter 39445P39.30Using the relativistic form,pmuucmu=−=12bgγwe find the difference ∆pfrom the classical momentum, mu:∆pmumumu=−=−γγ1.(a)The difference is 1.00% when −=100100mumu.:==−10990112.thus 99022−FHGIKJ=uc.af, and =0141..(b)The difference is 10.0% when 100mumu.:−10900112.thus 90022−FHGIKJ=uc.and=0436..P39.31umumu mumu−=−1:−−≈+FHGIKJFHGIKJ1111112112222ucucumu−=×FHGIKJ=×−1290 0300 10450 108214...msP39.32pmu=−12becomes1222ucmupwhich gives:1122=+FHGIKJumpcor cumcp21FHGIKJanducmc p=+22 21ej.P39.33Relativistic momentum of the system of fragments must be conserved. For total momentum to bezero after as it was before, we must have, with subscript 2 referring to the heavier fragment, and
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .