1105_Physics ProblemsTechnical Physics

1105_Physics - 446 Relativity Section 39.8 P39.34 Relativistic Energy b g E = 1 2 mc 2 mc 2 = 0.511 MeV For an electron F 1 1 I mc = 0.582 MeV GH

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446 Relativity Section 39.8 Relativistic Energy P39.34 Em c =− γγ 12 2 bg For an electron, mc 2 0511 = . M e V (a) c = F H G I K J = 1 10 8 1 0 1 2 5 0 0582 2 .. . a f a f MeV (b) c = F H G G I K J J = 1 9 9 0 1 8 1 0 245 2 2 . . . af MeV P39.35 WK K vc mc mc fi f i = F H G G G I K J J J F H G G I K J J 1 1 1 1 1 2 2 2 2 di or W mc f i = F H G G G I K J J J 1 1 1 1 22 2 (a) W = F H G G I K J J ×× 1 7 5 0 1 5 0 0 1 673 10 2 998 10 27 8 2 ej kg m s W 537 10 11 J (b) W = F H G G I K J J 1 9 9 5 1 5 0 0 1 673 10 2 998 10 27 8 2 kg m s W 133 10 9 J P39.36 The relativistic kinetic energy of an object of mass m and speed u is K uc mc r = F H G G I K J J 1 1 1 2 . For = 0100 . , Km c m c r = F H G I K J = 1 0 1 0 0 0 0 5 0 3 8 . The classical equation
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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