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1105_Physics ProblemsTechnical Physics

# 1105_Physics ProblemsTechnical Physics - 446 Relativity...

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446 Relativity Section 39.8 Relativistic Energy P39.34 E mc = γ γ 1 2 2 b g For an electron, mc 2 0 511 = . MeV (a) E mc = F H G I K J = 1 1 0 810 1 1 0 250 0 582 2 . . . a f a f MeV (b) E mc = F H G G I K J J = 1 1 0 990 1 1 0 810 2 45 2 2 . . . a f MeV P39.35 W K K v c mc v c mc f i f i = = F H G G G I K J J J F H G G I K J J 1 1 1 1 1 2 2 2 2 d i b g or W v c v c mc f i = F H G G G I K J J J 1 1 1 1 2 2 2 d i b g (a) W = F H G G I K J J × × 1 1 0 750 1 1 0 500 1 673 10 2 998 10 2 2 27 8 2 . . . . a f a f e je j kg m s W = × 5 37 10 11 . J (b) W = F H G G I K J J × × 1 1 0 995 1 1 0 500 1 673 10 2 998 10 2 2 27 8 2 . . . . a f a f e je j kg m s W = × 1 33 10 9 . J P39.36 The relativistic kinetic energy of an object of mass m and speed u is K u c mc r = F H G G I K
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