1112_Physics ProblemsTechnical Physics

# 1112_Physics ProblemsTechnical Physics - Chapter 39(a Since...

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Chapter 39 453 P39.59 (a) Since Mary is in the same reference frame, S , as Ted, she measures the ball to have the same speed Ted observes, namely ′= uc x 0800 .. (b) ∆′= = × × t L u p x 180 10 750 10 12 3 . . m 0.800 3.00 10 m s s 8 ej (c) LL v c c c p =− = × 1 1 80 10 1 0600 144 10 2 2 12 2 2 12 . . . m m af Since vc = . and ′=− x . , the velocity Jim measures for the ball is u uv uvc cc c x x x = ′+ +′ = −+ +− 1 0 800 0 600 1 0 800 0 600 0385 2 . a f a f . (d) Jim measures the ball and Mary to be initially separated by 1 44 10 12 . × m. Mary’s motion at 0.600 c and the ball’s motion at 0.385 c nibble into this distance from both ends. The gap closes at the rate 0 600 0 385 0 985 ... ccc += , so the ball and catcher meet after a time t = × × 488 10 12 3 . . m 0.985 3.00 10 m s s 8 . *P39.60 (a) The charged battery stores energy Et == = P 120 50 60 3600 . J s m i n sm i n J bg a f so its mass excess is m E c × 22 14 400 10 J 31 0 m s kg 8 (b) m m = × × 10 160 10 14 3 12 . . kg 25 kg too small to measure. P39.61 mc mc 2 2 4 938 78 3 728 4 100%
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