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1114_Physics ProblemsTechnical Physics

# 1114_Physics ProblemsTechnical Physics - Chapter 39 P39.65...

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Chapter 39 455 P39.65 Look at the situation from the instructors’ viewpoint since they are at rest relative to the clock, and hence measure the proper time. The Earth moves with velocity vc =− 0280 . relative to the instructors while the students move with a velocity ′=− uc 0600 . relative to Earth. Using the velocity addition equation, the velocity of the students relative to the instructors (and hence the clock) is: u vu vu c cc c c = + +′ = −− +− 1 0 280 0 600 1 0 280 0 600 0753 22 .. . af a f a fa f (students relative to clock). (a) With a proper time interval of t p = 50 0 . m in , the time interval measured by the students is: ∆∆ tt p = γ with = = 1 10 7 5 3 152 2 2 . . . Thus, the students measure the exam to last T == 152500 760 . min minutes . (b) The duration of the exam as measured by observers on Earth is: p = with = 1 2 8 0 2 2 . so T 104500 521 . min minutes . P39.66 The energy which arrives in one year is
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