1124_Physics ProblemsTechnical Physics

# 1124_Physics ProblemsTechnical Physics - Chapter 40 e je b5...

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Chapter 40 465 P40.4 (a) P == × × = × −− eA T σ 44 8 4 4 1 20 0 10 5 67 10 5 000 7 09 10 .. . m W m K K W 22 4 ej e j bg (b) λλ λ max max max . T × = 5 000 2 898 10 580 3 K m n m (c) We compute: hc kT B Js ms JK K m = ×⋅× × 6626 10 300 10 138 10 5000 288 10 34 8 23 6 . . e j The power per wavelength interval is π AI hc A hc k T 2 1 2 5 exp B , and 2 2 6626 10 200 10 750 10 23 4 8 2 41 9 ππ hc A × × = × ... . e j e j Jm s 4 580 580 10 2 88 1 115 10 1 799 10 19 9 5 13 4.973 10 nm ±Jm s m m 0.580 m Jms Wm 4 af = ×⋅ ×− = . exp . . . µµ e (d)–(i) The other values are computed similarly: (d) (e) (f) (c) (g) (h) (i) hc e hc A B hc k T B / () , 1.00 nm 2882.6 . . . 5.00 nm 576.5 . . . 400 nm 7.21 1347 . . 580 nm 4.97 143.5 . . 700 nm 4.12 60.4 . . 1.00 mm 0.00288 0.00289 . . 10.0 cm . . . . ×× × × × × × 1 2 7 96 10 7 50 10 9 42 10 2 40 10 2 40 10 1 00 10 7 32 10 5 44 10 1 15 10 7 99 10 4 46 10 7 38 10 0260 2 88 10 2 88 10 7 50 10 2 60 10 2 5 1251 26 1226 250 23 227 13 10 13 10 12 10 4 55 1 49 (j) We approximate the area under the versus curve, between 400 nm and 700 nm, as two trapezoids:
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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