1125_Physics ProblemsTechnical Physics

1125_Physics ProblemsTechnical Physics - 466 P40.6...

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466 Introduction to Quantum Physics P40.6 Eh f hc == = ×⋅× × λ 6626 10 300 10 589 3 10 337 10 34 8 9 19 .. . . Js ms m Jpho ton ej e j n E == × P 10 0 296 10 19 19 . . . photons s P40.7 (a) f × × × F H G I K J = −− 6 626 10 620 10 100 257 34 12 1 19 . . . s eV 1.60 10 J eV e j (b) f × × × F H G I K J 310 10 128 10 34 9 1 5 . . s eV 1.60 10 J eV 19 e j (c) f × × × F H G I K J 6 626 10 46 0 10 191 10 34 6 1 19 7 . . s eV 1.60 10 J eV e j (d) × × = c f 620 10 484 10 484 8 12 7 . . Hz m nm, visible light blue a f × × = × × = c f c f 968 10 968 46 0 10 652 8 9 2 8 6 . . . . . Hz m c m , r a d i o w a v e Hz m, radio wave P40.8 Energy of a single 500-nm photon: f hc γ × 500 10 398 10 34 8 9 19 . m J e j . The energy entering the eye each second Et I A t = ==× × L N M O Q P ∆∆ 400 10 4 8 5 01 0 1 0 0 2 2 71 0 11 3 2 15 . . Wm m s J 2 e j af π . The number of photons required to yield this energy n E E × × 227 10 10 571 10 15 19
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