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1127_Physics ProblemsTechnical Physics

1127_Physics ProblemsTechnical Physics - 468 Introduction...

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468 Introduction to Quantum Physics P40.14 K mv max max . . . . = = 1 × × = × = 1 2 2 9 11 10 4 60 10 9 64 10 0 602 2 31 5 2 20 e je j J eV (a) φ = = = E K max . . 1 240 0 602 1 38 eV nm 625 nm nm eV (b) f h c = = × × F H G I K J = × φ 1 38 1 60 10 3 34 10 34 19 14 . . . eV 6.626 10 J s J 1 eV Hz P40.15 (a) λ φ c hc = Li: λ c = × × × = 6 626 10 3 00 10 2 30 1 60 10 540 34 8 19 . . . . J s m s eV J eV nm e je j a f e j Be: λ c = × × × = 6 626 10 3 00 10 3 90 1 60 10 318 34 8 19 . . . . J s m s eV J eV nm e je j a f e j Hg: λ c = × × × = 6 626 10 3 00 10 4 50 1 60 10 276 34 8 19 . . . . J s m s eV J eV nm e je j a f e j λ λ < c for photo current. Thus, only lithium will exhibit the photoelectric effect. (b) For lithium, hc K λ φ = + max 6 626 10 3 00 10 400 10 2 30 1 60 10 1 29 10 0 808 34 8 9 19 19 . . . . . . max max × × × = × + = × = J s m s m eV J eV e je j a f e j K K P40.16 From condition (i), hf e V S =
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