1130_Physics ProblemsTechnical Physics

# 1130_Physics ProblemsTechnical Physics - Chapter 40 P40.25...

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Chapter 40 471 P40.25 (a) Conservation of momentum in the x direction gives: pp p e γγ θφ = + cos cos or since = , h p h e λλ θ 0 =+ F H G I K J cos . [1] Conservation of momentum in the y direction gives: 0 =′ e γ θθ sin sin , which (neglecting the trivial solution = 0) gives: h e =′= λ . [2] Substituting [2] into [1] gives: hh 0 2 = cos , or ′= 2 0 cos . [3] Then the Compton equation is ′− = 0 1 h mc e cos a f giving 21 00 λθ cos cos −= h e a f or 1 1 0 2 cos cos hc e af . Since E hc = 0 , this may be written as: 1 2 cos cos F H G I K J E e which reduces to: 22 + F H G I K J E E ee cos or cos .. . . = + + = + + = E E e e 2 2 2 0511 0880 0732 MeV MeV 1.02 MeV MeV so that == ° 43 0 (b) Using Equation (3): = ° E hc hc E 0 43 0 0602 602 cos cos . cos . . MeV
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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