1130_Physics ProblemsTechnical Physics

1130_Physics ProblemsTechnical Physics - Chapter 40 P40.25...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 40 471 P40.25 (a) Conservation of momentum in the x direction gives: pp p e γγ θφ = + cos cos or since = , h p h e λλ θ 0 =+ F H G I K J cos . [1] Conservation of momentum in the y direction gives: 0 =′ e γ θθ sin sin , which (neglecting the trivial solution = 0) gives: h e =′= λ . [2] Substituting [2] into [1] gives: hh 0 2 = cos , or ′= 2 0 cos . [3] Then the Compton equation is ′− = 0 1 h mc e cos a f giving 21 00 λθ cos cos −= h e a f or 1 1 0 2 cos cos hc e af . Since E hc = 0 , this may be written as: 1 2 cos cos F H G I K J E e which reduces to: 22 + F H G I K J E E ee cos or cos .. . . = + + = + + = E E e e 2 2 2 0511 0880 0732 MeV MeV 1.02 MeV MeV so that == ° 43 0 (b) Using Equation (3): = ° E hc hc E 0 43 0 0602 602 cos cos . cos . . MeV
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online