1131_Physics ProblemsTechnical Physics

# 1131_Physics ProblemsTechnical Physics - 472 P40.26...

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472 Introduction to Quantum Physics P40.26 The energy of the incident photon is Ep c hc 0 0 == γ λ . (a) Conserving momentum in the x direction gives pp p e φθ =+ cos cos , or since = , E c e 0 θ di cos . [1] Conserving momentum in the y direction (with φ = 0) yields 0 = e θθ sin sin , or h e = ′ = . [2] Substituting Equation [2] into Equation [1] gives E c hh 0 = + F H G I K J λλ cos , or ′= λθ 2 0 hc E cos . [3] By the Compton equation, ′− = 0 1 h mc e cos af , 22 1 00 hc E hc E h e cos cos −= which reduces to 2 2 0 2 0 E E ee += + ej cos . Thus, + + F H G I K J cos 1 2 0 2 0 2 E E e e . (b) From Equation [3], = + + F H G I K J 2 2 0 2 0 hc E hc E E E e e cos . Therefore, = ++ = + + F H G I K J E hc hc hc E m c E m c E Em c E E e e 2 2 0 2 0 2 0 0 2 0 2 0 bg e j , and = + + F H G I K J p E c E c E E e e 0 2 0 2 0 2 2 . (c) From conservation of energy,
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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