1136_Physics ProblemsTechnical Physics

1136_Physics ProblemsTechnical Physics - 477 Chapter 40 (a)...

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Chapter 40 477 P40.35 (a) Electron: λ = h p and Km v mv m p m e e ee == = 1 22 2 2 2 so pm K e = 2 and ×⋅ ×× −− h mK e 2 6626 10 2 9 11 10 3 00 1 60 10 34 31 19 . .. . Js kg J ej af = 709 10 0709 10 m n m . (b) Photon: = c f and Eh f = so f E h = and ×⋅× × = hc E 300 10 3 1 60 10 414 10 414 34 8 19 7 . . ms J n m e j . P40.36 (a) The wavelength of a non-relativistic particle of mass m is given by h p h mK 2 where the kinetic energy K is in joules. If the neutron kinetic energy K n is given in electron volts, its kinetic energy in joules is KK n 160 10 19 . J e V and the equation for the wavelength becomes = × h mK K K n n 2 2 1 67 10 1 60 10 287 10 34 27 19 11 . . kg J eV m e j where K n is expressed in electron volts. (b) If K n 100 1000 . keV eV, then = × = 907 10 907 11 13 . . m f m . P40.37 (a) ~10 14 m or less. p h = =⋅ ~ . 66 10 10 10 34 14 19 m kg m s or more. The energy of the electron is Ep c m
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