1138_Physics ProblemsTechnical Physics

1138_Physics ProblemsTechnical Physics - Chapter 40 P40.41...

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Chapter 40 479 P40.41 λ = h p p h == ×⋅ × 6626 10 100 10 663 10 34 11 23 . . . Js m kg m s (a) electrons: K p m e e × × = 2 23 2 31 2 2 9 11 10 15 1 . . . ej J k e V The relativistic answer is more precisely correct: Kp c m c m c ee e =+ = 22 24 2 14 9 . k eV. (b) photons: Ep c γ × × = 6 63 10 3 00 10 124 23 8 .. e j keV P40.42 (a) The wavelength of the student is h p h mv . If w is the width of the diffracting aperture, then we need w h mv ≤= F H G I K J 10 0 10 0 so that v h mw F H G I K J 10 0 10 0 80 0 0 750 110 10 34 34 . . kg m ms bg af . (b) Using t d v = we get: t × 0150 136 10 33 . . m 1.10 10 m s s 34 . (c) No . The minimum time to pass through the door is over 10 15 times the age of the Universe. Section 40.6 The Quantum Particle *P40.43 EK m u h f = 1 2 2 and = h mu . vf mu h h mu u v phase phase = = 2 . This is different from the speed u at which the particle transports mass, energy, and momentum.
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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