1142_Physics ProblemsTechnical Physics

1142_Physics ProblemsTechnical Physics - Chapter 40 P40.55...

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Chapter 40 483 P40.55 We want an Einstein plot of K max versus f λ , nm , Hz , eV 588 505 445 5.10 5.94 6.74 0.67 0.98 1.35 fK 10 14 max 399 7.52 1.63 (a) slope 0402 8% . e V 10 Hz 14 (b) eV h f S ∆=− φ h = ×⋅ F H G I K J ± 160 10 6 4 10 8% 19 34 . . . a f Js 10 14 (c) K max = 0 at f ≈× 344 10 12 Hz == × = hf 232 10 14 19 .. J e V f (THz) FIG. P40.55 P40.56 From the path the electrons follow in the magnetic field, the maximum kinetic energy is seen to be: K eBR m e max = 222 2 . From the photoelectric equation, Kh f hc max =−= − . Thus, the work function is λλ =− = hc K hc e B R m e max
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