1158_Physics ProblemsTechnical Physics

1158_Physics - Chapter 41 z z FGH IJK z cos 2L x IJK dx F x 1 sin 2 x IJ = FG 1 1 sin 2 IJ = FG 1 3 IJ = 0.196 P=G H L 2 L K H 3 2 3 K H 3 4 K L3

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Chapter 41 499 P41.21 (a) The probability is Pd x L x L dx L x L dx LL L == F H G I K J =− F H G I K J zz z ψ ππ 2 0 3 2 0 3 0 3 22 1 2 1 2 2 sin cos P x L x L L F H G I K J F H G I K J F H G I K J = 1 2 2 1 3 1 2 2 3 1 3 3 4 0196 0 3 π sin sin . . (b) The probability density is symmetric about x L = 2 . Thus, the probability of finding the particle between x L = 2 3 and xL = is the same 0.196. Therefore, the probability of finding it in the range L x L 3 2 3 ≤≤ is P = 100 20196 0609 .. . a f . FIG. P41.21(b) (c) Classically, the electron moves back and forth with constant speed between the walls, and the probability of finding the electron is the same for all points between the walls. Thus, the classical probability of finding the electron in any range equal to one-third of the available
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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