1161_Physics ProblemsTechnical Physics

1161_Physics ProblemsTechnical Physics - 502 *P41.30...

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502 Quantum Mechanics *P41.30 The original tunneling probability is Te CL = 2 where C mU E = = ×× × ×⋅ −− 2 229 1 11 0 1 2 1 61 0 6626 10 14481 10 12 31 19 34 10 1 af ch ej = π .. . . kg 20 J Js m. The photon energy is hf hc == = λ 1240 227 eV nm 546 nm eV . , to make the electron’s new kinetic energy 12 2 27 14 27 += . . eV and its decay coefficient inside the barrier ′ = × C 1 0 2 01 4 2 7 1 0 12255 10 31 19 34 10 1 . . . kg J m . Now the factor of increase in transmission probability is e e ee e CL CL LC C −′ ′×× × = = 2 2 2 21 0 02 2 31 0 4 . 4 5 91 0 1 85 9 m m . Section 41.7 The Scanning Tunneling Microscope P41.31 With the wave function proportional to e CL , the transmission coefficient and the tunneling current are proportional to ψ 2 , to e CL 2 . Then, I I e e e 0500 0515 135 2100 20 0 0 015 . . . nm nm nm nm nm nm a f a f bg = . P41.32 With transmission coefficient e CL 2 , the fractional change in transmission is
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