1172_Physics ProblemsTechnical Physics

1172_Physics ProblemsTechnical Physics - Chapter 41 2 2...

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Chapter 41 513 P41.55 With one slit open P 11 2 = ψ or P 22 2 = . With both slits open, P =+ ψψ 12 2 . At a maximum, the wave functions are in phase P max 2 ch . At a minimum, the wave functions are out of phase P min =− 2 . Now P P 1 2 1 2 2 2 25 0 == . , so 1 2 500 = . and P P max min . . . . . . . = + = + = 2 2 2 2 2 2 600 400 36 0 16 0 225 af . ANSWERS TO EVEN PROBLEMS P41.2 1 2 P41.22 (a) π 1 2 x L x L = F H G I K J cos ; Px L x L 1 2 2 = F H G I K J cos ; 2 2 2 x L x L = F H G I K J sin ; L x L 2 2 2 2 = F H G I K J sin ; 3 2 3 x L x L = F H G I K J cos ; L x L 3 2 2 3 = F H G I K J cos ; P41.4 (a) 4; (b) 6 03 . e V P41.6 0517 M e V , 331 10 20 . ×⋅ kg m s P41.8 3 8 h mc e λ F H G I K J P41.10 (a) 5 13 . meV ; (b) 9 41 . eV; (c) The much smaller mass of the electron requires it to have much more energy to have the same momentum. (b) see the solution P41.12 (a) 15 8 h e F H G I K J ; (b) 125 . P41.24 (a) = 2 2 2 2 2 4 6 mL x L F H G I K J ; (b) see the solution P41.26 see the solution P41.14
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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