522 Atomic PhysicsP42.10Starting with12222mvkeree=we havevmree22=and usingrnmkenee=2=givesvmnnee222==ejorvnne=2=.P42.11Each atom gives up its kinetic energy in emitting a photon,so126626 10300 101216 10163 102348718mvhc==×⋅××=×−−−λ....JsmsmJejv442 104. ms.P42.12The batch of excited atoms must make these six transitions to get back to state one: 21→, and also32→and 31→, and also 43→and 42→and 41→. Thus, the incoming light must have justenough energy to produce the 14→transition. It must be the third line of the Lyman series in theabsorption spectrum of hydrogen. The absorbing atom changes from energyEi=−13 613 6..eV1eV2to Ef13 60850..eV4eV2,so the incoming photons have wavelength=−=−−−×FHGIKJ=−−−hcEEfi136
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .