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1198_Physics ProblemsTechnical Physics

# 1198_Physics ProblemsTechnical Physics - Chapter 42 The...

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Chapter 42 539 P42.62 (a) The length of the pulse is ∆∆ Lc t = . (b) The energy of each photon is E hc γ λ = so N E E E hc == . (c) VL d =∆ π 2 4 n N V ct d E hc F H G I K J F H G I K J 4 2 *P42.63 The fermions are described by the exclusion principle. Two of them, one spin-up and one spin- down, will be in the ground energy level, with dL NN 1 2 , 2 L h p , and p h L = 2 Km v p m h mL = 1 22 8 2 2 2 2 . The third must be in the next higher level, with d L NN , = L , and p h L = K p m h mL 2 2 2 2 2 . The total energy is then h mL h mL h mL h mL 2 2 2 2 2 2 2 2 882 3 4 ++= . P42.64 z at F m t dB dz m x v z zz F H G I K J = F H G I K J 2 0 2 0 2 2 1 µ bg and z e e m = = 2 dB dz mz vm xe dB dz z e z ×× × = −− 2108 166 10 10 2 911 10 1 00 1 60 10 1 05 10 0389 0 2 2 27 3 4 31 19 34 af ej e j e j e j e j e j = .. . . kg m m s kg m C J s Tm 2 P42.65 We use ψπ 20 3 12 0 2 1 4 0 s ra r a e a f =− F H G I K J . By Equation 42.24, Pr r r a r a e F H G I K J F H G I K J 4 1 8 2 2 0 3 0 2 0 πψ . (a) dP r dr r a r a r a a r a r a r aa e a f F H G I K J F H G I
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