1207_Physics ProblemsTechnical Physics

# 1207_Physics ProblemsTechnical Physics - 548 Molecules and...

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548 Molecules and Solids P43.2 We are told K Cl eV K Cl ++ → + +− 07 . and Cl e Cl eV +→ + −− 36 . or Cl Cl e eV →+− .. By substitution, K Cl eV K Cl+e eV K e V K + e +→ 43 . or the ionization energy of potassium is . eV. P43.3 (a) Minimum energy of the molecule is found from dU dr Ar Br =− + = 12 6 0 13 7 yielding r A B 0 16 2 = L N M O Q P . (b) EU U A AB B B A B A rr r =−= L N M M O Q P P L N M O Q P = =∞ = 0 0 4 2 1 4 1 24 22 This is also the equal to the binding energy, the amount of energy given up by the two atoms as they come together to form a molecule. (c) r 0 120 60 11 20124 10 1488 10 742 10 742 = ×⋅ L N M M O Q P P = . . eV m eV m m p m 12 6 ej E = = 40124 10 446 60 2 120 . . . eV m eV m eV 6 12 *P43.4 (a) We add the reactions K eV K e + 434 . and I e I eV +→+ 306 . to obtain K I K I eV + + 434 306 a f . The activation energy is 128 e V . (b) dU dr r r = F H G I K J + F H G I K J L N M M O Q
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## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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