Chapter 43561Section 43.8SuperconductivityP43.46(a)See the figure at right.(b)For a surface current around the outside of the cylinder as shown,BNI=µ0Aor NIB==××⋅=−−Aπ0270540250 1041010 7...T mTmAkAafej.FIG. P43.46P43.47By Faraday’s law (Equation 32.1),∆Φ∆∆∆∆∆BtLItABt.Thus,∆∆IABL×=−bgbg0010000200310 1020328.m THA.The direction of the induced current is such as to maintain the B–field through the ring.P43.48(a)∆VIR=If R=0 , then ∆V=0 , even when I≠0.(b)The graph shows a direct proportionality.SlopemAmV== =−−==−1155 57 8361 135643 1002321RIVR∆∆ΩΩ...(c)Expulsion of magnetic flux and therefore fewercurrent-carrying paths could explain the
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