1237_Physics ProblemsTechnical Physics

1237_Physics ProblemsTechnical Physics - 578 Nuclear...

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578 Nuclear Structure P44.28 RR e t = 0 λ where == ln . . 2 26 0 00266 1 h h R R e t 0 0100 . so ln . af =− t 230 . . = F H G I K J h t t = 86 4 . h P44.29 The number of nuclei which decay during the interval will be NNN e e tt 120 12 −= −− λλ ej . First we find l : = ln . . .. 20 6 9 3 64 8 0 010 7 2 97 10 16 1 T h h s and N R 0 0 41 61 11 40 0 3 70 10 297 10 498 10 × × µµ . . Ci s Ci s nuclei bg . Substituting these values, NN e e 11 00107 100 11 × L N M O Q P . h h . Hence, the number of nuclei decaying during the interval is 9 947 10 × . n u c l e i . P44.30 The number of nuclei which decay during the interval will be e e . First we find : = ln2 T so ee t tT 2 and N R RT 0 0 012 2 ln . Substituting in these values 22 2 21 2 = ln ln e j . *P44.31 We have all this information: xy 02 5 0 0 = . Ne N e T T x x x x yy x y 34 2 0 3 04 2 0 2 0 0 250 25 42 3 3 3 0693
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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