1239_Physics ProblemsTechnical Physics

1239_Physics ProblemsTechnical Physics - 580 P44.34 Nuclear...

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580 Nuclear Structure P44.34 (a) A gamma ray has zero charge and it contains no protons or neutrons. So for a gamma ray Z = 0 and A = 0. Keeping the total values of Z and A for the system conserved then requires Z = 28 and A = 65 for X . With this atomic number it must be nickel, and the nucleus must be in an exited state, so it is 28 65 Ni * . (b) α = 2 4 He has Z = 2 and A = 4 so for X we require Z =−= 84 2 82 for Pb and A =− = 215 4 211, X = 82 211 Pb. (c) A positron e e + = 1 0 has charge the same as a nucleus with Z = 1. A neutrino 0 0 ν has no charge. Neither contains any protons or neutrons. So X must have by conservation Z =+ = 26 1 27. It is Co. And A =+= 55 0 55. It is 27 55 Co. Similar reasoning about balancing the sums of Z and A across the reaction reveals: (d) 1 0 e (e) 1 1 H (or p). Note that this process is a nuclear reaction, rather than radioactive decay. We can solve it from the same principles, which are fundamentally conservation of charge and conservation of baryon number. P44.35 N C = F H G I K J × 00210 602 10 23 . . g 12.0 g mol molecules mol ej N C 105 10 21 . carbon atoms of which 1 in 7 70 10
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