1245_Physics ProblemsTechnical Physics

1245_Physics ProblemsTechnical Physics - 586 Nuclear...

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586 Nuclear Structure Additional Problems *P44.54 (a) With m n and v n as the mass and speed of the neutrons, Eq. 9.23 of the text becomes, after making appropriate notational changes, for the two collisions v m mm v n n n 1 1 2 = + F H G I K J , v m v n n n 2 2 2 = + F H G I K J ∴+ =+ = ∴− = ∴= v mm v m v mv v mv mv m mv mv vv nnn n n n 22 11 21 1 1 2 2 2 bg (b) m n = ×− × × = 1 3 30 10 14 4 70 10 4 70 10 3 30 10 116 76 67 u m s m s ms u af ej .. . P44.55 (a) QM M M m c n =+− 94 1 2 2 Be He C Q − − = 9 012 182 4 002 603 12 000 000 1 008 665 931 5 5 70 . . u u u u MeV u MeV (b) M m n =− 2 23 HH e Q = 2 2 014 3 016 029 1 008 665 3 27 . . 102 u 931.5 MeV u MeV exothermic b g a f P44.56 (a) At threshold, the particles have no kinetic energy relative to each other. That is, they move like two particles that have suffered a perfectly inelastic collision. Therefore, in order to calculate the reaction threshold energy, we can use the results of a perfectly inelastic collision. Initially, the projectile M a moves with velocity v a while the target M X is at rest. We have from momentum conservation for the projectile-target system: Mv M M v aa a X c . The initial energy is:
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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