1250_Physics ProblemsTechnical Physics

1250_Physics ProblemsTechnical Physics - Chapter 44 P44.68...

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Chapter 44 591 P44.68 (a) Add two electrons to both sides of the reaction to have it in energy terms: 4 1 1 H atom He atom 2 4 →+ Q Qm c M M c == 22 4 1 1 2 4 HH e Q =− × F H G I K J 4 1 007 825 4 002 603 931 5 160 10 428 10 13 12 .. . . . u u M e V u J 1 MeV J bg b g (b) N = × × = × 199 10 1 19 10 119 10 30 27 57 57 . kg 1.67 10 kg atom atoms protons (c) The energy that could be created by this many protons in this reaction is: 127 10 57 12 45 . . . × × F H G I K J protons J 4 protons J ej P = E t so t E × × = 338 10 107 45 18 . . J 3.77 10 W s billion years 26 . P44.69 E =− ⋅ µ B so the energies are EB 1 =+ and 2 µµ = 27928 . n and n 505 10 27 . J T × = × −− 2 2 2 792 8 5 05 10 12 5 3 53 10 2 20 10 27 25 6 . af JT T J eV . P44.70 (a) λ × F H G I K J ln ln . . 527 1 417 10 12 91 T yr yr 3.156 10 s s 7 t × F H G I K J 30 0 2 50 3156 10 789 10 7 7 . . months yr s 1 yr s RR e Ne tt 00 λλ so N R ee t 0 10 4.17 10 7 89 10 10 0 3 70 10 7 = F H G I K J = × × L N M M O Q P P ×× . . Ci Bq Ci s s
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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