1262_Physics ProblemsTechnical Physics

1262_Physics ProblemsTechnical Physics - Chapter 45 Section...

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Chapter 45 603 Section 45.5 Radiation Damage P45.23 N 0 27 25 500 166 10 335 10 == × mass present mass of nucleus kg 89.907 7 u kg u nuclei . . . bg ej λ ==× × = × × −− ln ln . .. . . . . 22 29 1 2 38 10 4 52 10 4 52 10 3 35 10 1 52 10 10 0 152 10 660 10 12 21 8 1 00 81 2 5 1 8 0 18 18 T RN R R e t yr yr min min counts min counts min counts min e j and t =− × = ln . . 396 18 giving t × 39 6 39 6 238 10 3 . . yr yr . P45.24 Source: 100 mrad of 2-MeV γ - rays/h at a 1.00-m distance. (a) For -rays, dose in rem = dose in rad. Thus a person would have to stand 10 0 . hours to receive 1.00 rem from a 100-mrad/h source. (b) If the - radiation is emitted isotropically, the dosage rate falls off as 1 2 r . Thus a dosage 10.0 mrad/h would be received at a distance r 10 0 3 16 m m . P45.25 (a) The number of x-rays taken per year is n × 8 5 50 2 0 10 3 x-ray d d wk wk yr x-ray yr b g b g The average dose per photograph is
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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