1264_Physics ProblemsTechnical Physics

# 1264_Physics ProblemsTechnical Physics - Chapter 45...

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Chapter 45 605 P45.32 (a) E I = 10 0 . eV is the energy required to liberate an electron from a dynode. Let n i be the number of electrons incident upon a dynode, each having gained energy eV af as it was accelerated to this dynode. The number of electrons that will be freed from this dynode is Nn e V E ii I = : At the first dynode, n i = 1 and N e 1 1 11 0 0 10 0 10 == a f a f V eV electrons . . (b) For the second dynode, nN i 1 1 10 ,s o N e 2 1 2 10 100 10 0 10 () . V eV . At the third dynode, i 2 2 10 and N e 3 2 3 10 100 10 0 10 . V eV a f . Observing the developing pattern, we see that the number of electrons incident on the seventh and last dynode is 76 6 10 . (c) The number of electrons incident on the last dynode is n 7 6 10 = . The total energy these electrons deliver to that dynode is given by En e i = a f 10 700 600 10 68 V V e V . P45.33 (a) The average time between slams is 60 38 1 6 min min = . . Sometimes, the actual interval is nearly zero. Perhaps about equally as often, it is 2 1 6 × . min. Perhaps about half as often, it is 41 6 × . m in. Somewhere around 51 6 8 0 ×= .. min min , the chances of randomness producing so long a wait get slim, so such a long wait might likely be due to mischief.
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## This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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