608 Applications of Nuclear Physics(c)The energy released is the energy of reaction of the number of carbon nuclei in a 2.00-kgsample, which corresponds to∆∆EE=××FHGIKJFHGIKJ×FHGIKJ=××200 10602 1012 046221100 102 2 25 10103 1032326197........gatoms molgmolMeV fusion eventnuclei fusion eventkWh2.25 10 MeVkWhkWh19ejafP45.40To conserve momentum, the two fragments must move in opposite directions with speeds v1andv2such thatmv1122=orvmmv2121=FHGIKJ.The kinetic energies after the break-up are thenKmv1212=andvmmmvmmK222122121211212==FHGIKJ=FHGIKJ.The fraction of the total kinetic energy carried off by m1isKKKKmKmmm1121212+=+=+bgand the fraction carried off by m2is121−+=+mm.*P45.41(a)Qcccc=−−==236 045 56286 920 711148 934 3700 190 48117722..uuuuMeVImmediately after fission, this
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .