1267_Physics ProblemsTechnical Physics

# 1267_Physics ProblemsTechnical Physics - 608 Applications...

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608 Applications of Nuclear Physics (c) The energy released is the energy of reaction of the number of carbon nuclei in a 2.00-kg sample, which corresponds to E E × F H G I K J F H G I K J × F H G I K J = × × 200 10 602 10 12 0 462 2 1 100 10 2 2 25 10 103 10 3 23 26 19 7 . . . . .. . . g atoms mol gmo l MeV fusion event nuclei fusion event kWh 2.25 10 MeV kWh kWh 19 ej af P45.40 To conserve momentum, the two fragments must move in opposite directions with speeds v 1 and v 2 such that mv 11 22 = or v m m v 2 1 2 1 = F H G I K J . The kinetic energies after the break-up are then Km v 1 2 1 2 = and vm m m v m m K 2 2 2 1 2 2 1 2 1 2 1 1 2 1 2 == F H G I K J = F H G I K J . The fraction of the total kinetic energy carried off by m 1 is K KK K m K m mm 1 12 1 2 1 2 + = + = + bg and the fraction carried off by m 2 is 1 2 1 + = + m m . *P45.41 (a) Qcc c c =− −= = 236 045 562 86 920 711 148 934 370 0 190 481 177 2 2 . . uu u u M e V Immediately after fission, this
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## This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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