1269_Physics ProblemsTechnical Physics

1269_Physics ProblemsTechnical Physics - 610 P45.46...

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610 Applications of Nuclear Physics P45.46 When mass m of 235 U undergoes complete fission, releasing 200 MeV per fission event, the total energy released is: Q m N = F H G I K J 235 200 gmo l MeV A a f where N A is Avogadro’s number. If all this energy could be utilized to convert a mass m w of liquid water at T c into steam at T h , then, Qmc T L cT ww c v sh + + ° 100 100 CC bg where c w is the specific heat of liquid water, L v is the latent heat of vaporization, and c s is the specific heat of steam. Solving for the mass of water converted gives m Q cT L c T mN L c T w wc v s h v s h = °− + + − ° = 100 100 200 235 100 100 MeV l C C A af . P45.47 (a) The number of molecules in 1.00 liter of water (mass = 1 000 g) is N = × F H G I K J ×= × 100 10 6 02 10 3 34 10 3 23 25 . .. g 18.0 g mol molecules mol molecules ej . The number of deuterium nuclei contained in these molecules is ′= × F H G I K J N 334 10 1 101 10 25 22 molecules deuteron 3300 molecules deuterons . Since 2 deuterons are consumed per fusion event, the number of events possible is N 2 507 10 21 . reactions, and the energy released is
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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