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1273_Physics ProblemsTechnical Physics

1273_Physics ProblemsTechnical Physics - 614 Applications...

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614 Applications of Nuclear Physics (d) E n = × the number of C atoms in 1.00 kg 4.20 eV E n = × F H G I K J × × = 6 02 10 12 4 20 10 4 44 10 9 36 26 6 20 . . . . MeV kWh e je j (e) Coal is cheap at this moment in human history. We hope that safety and waste disposal problems can be solved so that nuclear energy can be affordable before scarcity drives up the price of fossil fuels. P45.56 Add two electrons to both sides of the given reaction. Then 4 1 1 H atom He atom 2 4 + Q where Q m c = = = a f b g b g 2 4 1 007 825 4 002603 26 7 . . . u 931.5 MeV u MeV or Q = × = × 26 7 1 60 10 4 28 10 13 12 . . . MeV J MeV J a f e j . The proton fusion rate is then rate power output energy per proton J s J 4 protons protons s = = × × = × 3 77 10 4 28 10 3 53 10 26 12 38 . . . e j b g . P45.57 (a) Q M M M M c I A B C E = + 2 , and Q M M M M c II C D F G = + 2 Q Q Q M M M M M M M M c net I II A B C E C D F
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