1284_Physics ProblemsTechnical Physics

# 1284_Physics ProblemsTechnical Physics - Chapter 46 P46.16...

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Chapter 46 625 P46.16 Momentum conservation for the decay requires the pions to have equal speeds. The total energy of each is 497 7 . M eV 2 so Ep c m c 2 =+ 22 2 2 ej gives 248 8 139 6 2 2 2 .. MeV MeV af bg pc . Solving, pc mvc mc vc v c == = F H G I K J 206 1 2 2 MeV γ pc mc v c 2 2 206 1 1 148 F H G I K J = MeV 139.6 MeV . v c v c =− F H G I K J 148 1 2 . and v c v c v c F H G I K J F H G I K J L N M M O Q P P F H G I K J 2 218 1 218 218 . 318 218 2 v c F H G I K J = so v c 0828 . . . and = P46.17 (a) p ++ →+ ππ 0 Baryon number : 100 (b) p p p p +→++ π 0 This reaction can occur . (c) p p p +→+ Baryon number is violated:
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## This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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