1284_Physics ProblemsTechnical Physics

# 1284_Physics ProblemsTechnical Physics - Chapter 46 P46.16...

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Chapter 46 625 P46.16 Momentum conservation for the decay requires the pions to have equal speeds. The total energy of each is 497 7 . MeV 2 so E p c mc 2 = + 2 2 2 2 e j gives 248 8 139 6 2 2 2 . . MeV MeV a f b g a f = + pc . Solving, pc mvc mc v c v c = = = F H G I K J 206 1 2 2 MeV γ b g pc mc v c v c 2 2 206 1 1 1 48 = = F H G I K J = MeV 139.6 MeV b g . v c v c = F H G I K J 1 48 1 2 . and v c v c v c F H G I K J = F H G I K J L N M M O Q P P = F H G I K J 2 2 2 2 18 1 2 18 2 18 . . . 3 18 2 18 2 . . v c F H G I K J = so v c = = 2 18 3 18 0 828 . . . and v c = 0 828 . . P46.17 (a) p + + + π π 0 Baryon number : 1 0 0 + (b) p p p p + + + + + + + π 0 This reaction can occur . (c) p p p
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