626 Particle Physics and CosmologyP46.18(a)pe→++γBaryon number:+→ +100∆B≠0, so baryon number conservation is violated.(b)From conservation of momentum for the decay:ppe=.Then, for the positron,EpcEeee2202=+bg,becomesEEe2202202=+γγdi,,.From conservation of energy for the system:EEEpe0,orEE Eep=−soEp202022+.Equating this to the result from above givesEEEp20202022+=−+,orEEp=−=−=0202029383051129383469,...MeVMeVMeVMeVaf.Thus,=−=0938 3469469,.MeVMeVMeV .Also,pEcc==469 MeVandce469 MeV.(c)The total energy of the positron isEe=469 MeV .But,Evce−0021,,so1109 10203−FHGIKJ=×−vcEEee,..MeV469 MeVwhich yields:=09999994..P46.19
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This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .