1289_Physics ProblemsTechnical Physics

1289_Physics ProblemsTechnical Physics - 630 P46.25...

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630 Particle Physics and Cosmology P46.25 (a) Kp ? p + +→ + The strong interaction conserves everything. Baryon number, 0 1 1 B so B = 0 Charge, ++ → + 11 1 Q so Q =+ 1 Lepton numbers, 00 0 +→+ L so LL L e === µτ 0 Strangeness, 10 0 S so S = 1 The conclusion is that the particle must be positively charged, a non-baryon, with strangeness of +1. Of particles in Table 46.2, it can only be the K + . Thus, this is an elastic scattering process. The weak interaction conserves all but strangeness, and S 1. (b) −− →+ ? π Baryon number, B so B = 1 Charge, −→ − Q so Q = 0 Lepton numbers, 0 0 L so e 0 Strangeness, −→ + 30 S so S = 1: S =− 2 The particle must be a neutral baryon with strangeness of –2. Thus, it is the
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