1302_Physics ProblemsTechnical Physics

# 1302_Physics ProblemsTechnical Physics - Chapter 46 P46.62...

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Chapter 46 643 P46.62 πµ ν µ −− →+ : From the conservation laws for the decay, mc E E 2 139 6 == + . M eV [1] and pp µν = , Ep c νν = : c p c µµ 2 2 2 2 2 105 7 105 7 =+ di af bg .. MeV MeV or EE 22 2 105 7 −= . [2] Since += 139 6 . MeV [1] and µνµν +− = a f 105 7 2 [2] then = 105 7 139 6 80 0 2 . . . MeV MeV . [3] Subtracting [3] from [1], 2 59 6 E = and E = 29 8 eV . P46.63 The expression ed E EkT B gives the fraction of the photons that have energy between E and Ed E + . The fraction that have energy between E and infinity is E E E k T E k T e e e E E E z z z z = B B B B B B B B B 00 0 . We require T when this fraction has a value of 0.0100 (i.e., 1.00%) and E × 1 00 1 60 10 19 eV J. Thus, 00100 1.60 10 1.38 10 19 23 . = −× × e T J J K ej e j or ln . 1 60 10 1 16 10 19 23 4 =− × × × J 1.38 10 J K K T T giving T 252 10 3 . K . P46.64 (a) This diagram represents the annihilation of an
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## This note was uploaded on 12/15/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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