Practice equilibrium questions

Practice equilibrium questions - Ans Ans: c Ans Ans: b Ans...

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Unformatted text preview: Ans Ans: c Ans Ans: b Ans Ans: B ANS: ANS: B Ans: c Ans Ans: C Ans:C Ans:C ANS: ANS: D Ans Ans: c Ans Ans: a Ans Ans: B Ans Ans: d Ans Ans: A ANS: ANS: B Ans Ans: B Ans Ans: c Ans Ans: left, right, darker Ans Ans: A ANS: ANS: D Ans Ans: C ANS: ANS: B Ans Ans: D ANS: ANS: D Ans Ans: B Ans Ans: C ANS: ANS: C ANS: ANS: C ANS: ANS: D ANS: ANS: A ANS: ANS: A ANS: ANS: A ANS: ANS: C Sample Problem 18.8 Concentration (M) HPr(aq) + H2O(l) H3O+(aq) + Pr‐(aq) Initial 0.10 ‐ 0 0 Change −x ‐ +x +x ‐ x x 0.10 - x Equilibrium Since Ka is small, we will assume that x << 0.10 and [HPr] ≈ 0.10 M. Ka = 1.8x10‐5 = [H3O+][Pr‐] [HPr] x = (0.1 *1.8x10‐5) 1/2 Check: [HPr]diss = = x2 0.10 = 1.3x10‐3 M = [H3O+] 1.3x10‐3 M 0.10 M x 100 = 1.3% (< 5%; assumption is justified.) Ans Ans: D Ans Ans: C Ans Ans: B Ans Ans: A Ans Ans: B ANS: ANS: A ANS: ANS: C Ans Ans: B ANS: ANS: b Ans Ans: d Ans Ans: D ANS: ANS: b Ans Ans: B Ans Ans: B ...
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This note was uploaded on 12/15/2011 for the course CHM 139 taught by Professor Browning during the Spring '08 term at University of Toronto.

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